This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0101101012 = 010 110 101 = 010(=2) 110(=6) 101(=5) = 2658
the Final answer: 101101012 = 2658
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+0∙26+1∙25+1∙24+0∙23+1∙22+0∙21+1∙20 = 0∙256+1∙128+0∙64+1∙32+1∙16+0∙8+1∙4+0∙2+1∙1 = 0+128+0+32+16+0+4+0+1 = 18110
got It: 0101101012 =18110
Translate the number 18110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
181 | 8 | | |
-176 | 22 | 8 | |
5 | -16 | 2 | |
| 6 | | |
|
the result of the conversion was:
18110 = 2658
the Final answer: 101101012 = 2658