This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011001102 = 001 100 110 = 001(=1) 100(=4) 110(=6) = 1468
the Final answer: 11001102 = 1468
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+1∙26+1∙25+0∙24+0∙23+1∙22+1∙21+0∙20 = 0∙256+0∙128+1∙64+1∙32+0∙16+0∙8+1∙4+1∙2+0∙1 = 0+0+64+32+0+0+4+2+0 = 10210
got It: 0011001102 =10210
Translate the number 10210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
102 | 8 | | |
-96 | 12 | 8 | |
6 | -8 | 1 | |
| 4 | | |
|
the result of the conversion was:
10210 = 1468
the Final answer: 11001102 = 1468