This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
044C16 = 0 4 4 C = 0(=0000) 4(=0100) 4(=0100) C(=1100) = 100010011002
answer: 044C16 = 100010011002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙163+4∙162+4∙161+12∙160 = 0∙4096+4∙256+4∙16+12∙1 = 0+1024+64+12 = 110010
got It: 044C16 =110010
Translate the number 110010 в binary like this:
the Integer part of the number is divided by the base of the new number system:
1100 | 2 | | | | | | | | | | |
-1100 | 550 | 2 | | | | | | | | | |
0 | -550 | 275 | 2 | | | | | | | | |
| 0 | -274 | 137 | 2 | | | | | | | |
| | 1 | -136 | 68 | 2 | | | | | | |
| | | 1 | -68 | 34 | 2 | | | | | |
| | | | 0 | -34 | 17 | 2 | | | | |
| | | | | 0 | -16 | 8 | 2 | | | |
| | | | | | 1 | -8 | 4 | 2 | | |
| | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | 0 | | |
|
the result of the conversion was:
110010 = 100010011002
answer: 044C16 = 100010011002