This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011111012 = 001 111 101 = 001(=1) 111(=7) 101(=5) = 1758
answer: 011111012 = 1758
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+1∙26+1∙25+1∙24+1∙23+1∙22+0∙21+1∙20 = 0∙256+0∙128+1∙64+1∙32+1∙16+1∙8+1∙4+0∙2+1∙1 = 0+0+64+32+16+8+4+0+1 = 12510
got It: 0011111012 =12510
Translate the number 12510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
125 | 8 | | |
-120 | 15 | 8 | |
5 | -8 | 1 | |
| 7 | | |
|
the result of the conversion was:
12510 = 1758
answer: 011111012 = 1758