This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
13∙165+14∙164+10∙163+13∙162+1∙161+6∙160 = 13∙1048576+14∙65536+10∙4096+13∙256+1∙16+6∙1 = 13631488+917504+40960+3328+16+6 = 1459330210
got It: DEAD1616 =1459330210
Translate the number 1459330210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
14593302 | 8 | | | | | | | |
-14593296 | 1824162 | 8 | | | | | | |
6 | -1824160 | 228020 | 8 | | | | | |
| 2 | -228016 | 28502 | 8 | | | | |
| | 4 | -28496 | 3562 | 8 | | | |
| | | 6 | -3560 | 445 | 8 | | |
| | | | 2 | -440 | 55 | 8 | |
| | | | | 5 | -48 | 6 | |
| | | | | | 7 | | |
|
the result of the conversion was:
1459330210 = 675264268
answer: DEAD1616 = 675264268
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
DEAD1616 = D E A D 1 6 = D(=1101) E(=1110) A(=1010) D(=1101) 1(=0001) 6(=0110) = 1101111010101101000101102
answer: DEAD1616 = 1101111010101101000101102
let\'s make a direct translation from binary to post-binary like this:
1101111010101101000101102 = 110 111 101 010 110 100 010 110 = 110(=6) 111(=7) 101(=5) 010(=2) 110(=6) 100(=4) 010(=2) 110(=6) = 675264268
answer: DEAD1616 = 675264268