This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙162+1∙161+2∙160 = 0∙256+1∙16+2∙1 = 0+16+2 = 1810
got It: 01216 =1810
Translate the number 1810 в octal like this:
the Integer part of the number is divided by the base of the new number system:
18 | 8 | |
-16 | 2 | |
2 | | |
|
the result of the conversion was:
1810 = 228
answer: 01216 = 228
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
01216 = 0 1 2 = 0(=0000) 1(=0001) 2(=0010) = 100102
answer: 01216 = 100102
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0100102 = 010 010 = 010(=2) 010(=2) = 228
answer: 01216 = 228