This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
4658 = 4 6 5 = 4(=100) 6(=110) 5(=101) = 1001101012
answer: 4658 = 1001101012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
4∙82+6∙81+5∙80 = 4∙64+6∙8+5∙1 = 256+48+5 = 30910
got It: 4658 =30910
Translate the number 30910 в binary like this:
the Integer part of the number is divided by the base of the new number system:
309 | 2 | | | | | | | | |
-308 | 154 | 2 | | | | | | | |
1 | -154 | 77 | 2 | | | | | | |
| 0 | -76 | 38 | 2 | | | | | |
| | 1 | -38 | 19 | 2 | | | | |
| | | 0 | -18 | 9 | 2 | | | |
| | | | 1 | -8 | 4 | 2 | | |
| | | | | 1 | -4 | 2 | 2 | |
| | | | | | 0 | -2 | 1 | |
| | | | | | | 0 | | |
|
the result of the conversion was:
30910 = 1001101012
answer: 4658 = 1001101012