This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
A8D16 = A 8 D = A(=1010) 8(=1000) D(=1101) = 1010100011012
the Final answer: A8D16 = 1010100011012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
10∙162+8∙161+13∙160 = 10∙256+8∙16+13∙1 = 2560+128+13 = 270110
got It: A8D16 =270110
Translate the number 270110 в binary like this:
the Integer part of the number is divided by the base of the new number system:
2701 | 2 | | | | | | | | | | | |
-2700 | 1350 | 2 | | | | | | | | | | |
1 | -1350 | 675 | 2 | | | | | | | | | |
| 0 | -674 | 337 | 2 | | | | | | | | |
| | 1 | -336 | 168 | 2 | | | | | | | |
| | | 1 | -168 | 84 | 2 | | | | | | |
| | | | 0 | -84 | 42 | 2 | | | | | |
| | | | | 0 | -42 | 21 | 2 | | | | |
| | | | | | 0 | -20 | 10 | 2 | | | |
| | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
270110 = 1010100011012
the Final answer: A8D16 = 1010100011012