This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
2∙161+2∙160+6∙16-1+4∙16-2 = 2∙16+2∙1+6∙0.0625+4∙0.00390625 = 32+2+0.375+0.015625 = 34.39062510
got It: 22.6416 =34.39062510
Translate the number 34.39062510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
34 | 8 | |
-32 | 4 | |
2 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 390625*8 |
3 | .125*8 |
1 | .0*8 |
the result of the conversion was:
34.39062510 = 42.318
the Final answer: 22.6416 = 42.318
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
22.6416 = 2 2. 6 4 = 2(=0010) 2(=0010). 6(=0110) 4(=0100) = 100010.0110012
the Final answer: 22.6416 = 100010.0110012
let\'s make a direct translation from binary to post-binary like this:
100010.0110012 = 100 010. 011 001 = 100(=4) 010(=2). 011(=3) 001(=1) = 42.318
the Final answer: 22.6416 = 42.318