This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
65328 = 6 5 3 2 = 6(=110) 5(=101) 3(=011) 2(=010) = 1101010110102
answer: 65328 = 1101010110102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
6∙83+5∙82+3∙81+2∙80 = 6∙512+5∙64+3∙8+2∙1 = 3072+320+24+2 = 341810
got It: 65328 =341810
Translate the number 341810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3418 | 2 | | | | | | | | | | | |
-3418 | 1709 | 2 | | | | | | | | | | |
0 | -1708 | 854 | 2 | | | | | | | | | |
| 1 | -854 | 427 | 2 | | | | | | | | |
| | 0 | -426 | 213 | 2 | | | | | | | |
| | | 1 | -212 | 106 | 2 | | | | | | |
| | | | 1 | -106 | 53 | 2 | | | | | |
| | | | | 0 | -52 | 26 | 2 | | | | |
| | | | | | 1 | -26 | 13 | 2 | | | |
| | | | | | | 0 | -12 | 6 | 2 | | |
| | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the result of the conversion was:
341810 = 1101010110102
answer: 65328 = 1101010110102