This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
3∙81+2∙80+5∙8-1 = 3∙8+2∙1+5∙0.125 = 24+2+0.625 = 26.62510
got It: 32.58 =26.62510
Translate the number 26.62510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
26 | 16 | |
-16 | 1 | |
A | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 625*16 |
A | .0*16 |
the result of the conversion was:
26.62510 = 1A.A16
answer: 32.58 = 1A.A16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
32.58 = 3 2. 5 = 3(=011) 2(=010). 5(=101) = 011010.1012
answer: 32.58 = 11010.1012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
00011010.10102 = 0001 1010. 1010 = 0001(=1) 1010(=A). 1010(=A) = 1A.A16
answer: 00011010.10108 = 1A.A16