This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011100012 = 001 110 001 = 001(=1) 110(=6) 001(=1) = 1618
answer: 11100012 = 1618
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+1∙26+1∙25+1∙24+0∙23+0∙22+0∙21+1∙20 = 0∙256+0∙128+1∙64+1∙32+1∙16+0∙8+0∙4+0∙2+1∙1 = 0+0+64+32+16+0+0+0+1 = 11310
got It: 0011100012 =11310
Translate the number 11310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
113 | 8 | | |
-112 | 14 | 8 | |
1 | -8 | 1 | |
| 6 | | |
|
the result of the conversion was:
11310 = 1618
answer: 11100012 = 1618