This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
5∙81+6∙80 = 5∙8+6∙1 = 40+6 = 4610
got It: 568 =4610
Translate the number 4610 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
46 | 16 | |
-32 | 2 | |
E | | |
|
the result of the conversion was:
4610 = 2E16
the Final answer: 568 = 2E16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
568 = 5 6 = 5(=101) 6(=110) = 1011102
the Final answer: 568 = 1011102
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
001011102 = 0010 1110 = 0010(=2) 1110(=E) = 2E16
the Final answer: 001011108 = 2E16