This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
110111001.0110002 = 110 111 001. 011 000 = 110(=6) 111(=7) 001(=1). 011(=3) 000(=0) = 671.308
answer: 110111001.01102 = 671.308
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙28+1∙27+0∙26+1∙25+1∙24+1∙23+0∙22+0∙21+1∙20+0∙2-1+1∙2-2+1∙2-3+0∙2-4+0∙2-5+0∙2-6 = 1∙256+1∙128+0∙64+1∙32+1∙16+1∙8+0∙4+0∙2+1∙1+0∙0.5+1∙0.25+1∙0.125+0∙0.0625+0∙0.03125+0∙0.015625 = 256+128+0+32+16+8+0+0+1+0+0.25+0.125+0+0+0 = 441.37510
got It: 110111001.0110002 =441.37510
Translate the number 441.37510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
441 | 8 | | |
-440 | 55 | 8 | |
1 | -48 | 6 | |
| 7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 375*8 |
3 | .0*8 |
the result of the conversion was:
441.37510 = 671.38
answer: 110111001.01102 = 671.38