This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
AB0216 = A B 0 2 = A(=1010) B(=1011) 0(=0000) 2(=0010) = 10101011000000102
the Final answer: AB0216 = 10101011000000102
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
10∙163+11∙162+0∙161+2∙160 = 10∙4096+11∙256+0∙16+2∙1 = 40960+2816+0+2 = 4377810
got It: AB0216 =4377810
Translate the number 4377810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
43778 | 2 | | | | | | | | | | | | | | | |
-43778 | 21889 | 2 | | | | | | | | | | | | | | |
0 | -21888 | 10944 | 2 | | | | | | | | | | | | | |
| 1 | -10944 | 5472 | 2 | | | | | | | | | | | | |
| | 0 | -5472 | 2736 | 2 | | | | | | | | | | | |
| | | 0 | -2736 | 1368 | 2 | | | | | | | | | | |
| | | | 0 | -1368 | 684 | 2 | | | | | | | | | |
| | | | | 0 | -684 | 342 | 2 | | | | | | | | |
| | | | | | 0 | -342 | 171 | 2 | | | | | | | |
| | | | | | | 0 | -170 | 85 | 2 | | | | | | |
| | | | | | | | 1 | -84 | 42 | 2 | | | | | |
| | | | | | | | | 1 | -42 | 21 | 2 | | | | |
| | | | | | | | | | 0 | -20 | 10 | 2 | | | |
| | | | | | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
4377810 = 10101011000000102
the Final answer: AB0216 = 10101011000000102