This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1111011111011112 = 111 101 111 101 111 = 111(=7) 101(=5) 111(=7) 101(=5) 111(=7) = 757578
answer: 1111011111011112 = 757578
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙214+1∙213+1∙212+1∙211+0∙210+1∙29+1∙28+1∙27+1∙26+1∙25+0∙24+1∙23+1∙22+1∙21+1∙20 = 1∙16384+1∙8192+1∙4096+1∙2048+0∙1024+1∙512+1∙256+1∙128+1∙64+1∙32+0∙16+1∙8+1∙4+1∙2+1∙1 = 16384+8192+4096+2048+0+512+256+128+64+32+0+8+4+2+1 = 3172710
got It: 1111011111011112 =3172710
Translate the number 3172710 в octal like this:
the Integer part of the number is divided by the base of the new number system:
31727 | 8 | | | | |
-31720 | 3965 | 8 | | | |
7 | -3960 | 495 | 8 | | |
| 5 | -488 | 61 | 8 | |
| | 7 | -56 | 7 | |
| | | 5 | | |
|
the result of the conversion was:
3172710 = 757578
answer: 1111011111011112 = 757578