This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
15∙162+15∙161+9∙160 = 15∙256+15∙16+9∙1 = 3840+240+9 = 408910
got It: FF916 =408910
Translate the number 408910 в octal like this:
the Integer part of the number is divided by the base of the new number system:
4089 | 8 | | | |
-4088 | 511 | 8 | | |
1 | -504 | 63 | 8 | |
| 7 | -56 | 7 | |
| | 7 | | |
|
the result of the conversion was:
408910 = 77718
the Final answer: FF916 = 77718
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
FF916 = F F 9 = F(=1111) F(=1111) 9(=1001) = 1111111110012
the Final answer: FF916 = 1111111110012
let\'s make a direct translation from binary to post-binary like this:
1111111110012 = 111 111 111 001 = 111(=7) 111(=7) 111(=7) 001(=1) = 77718
the Final answer: FF916 = 77718