This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
11308 = 1 1 3 0 = 1(=001) 1(=001) 3(=011) 0(=000) = 0010010110002
answer: 11308 = 10010110002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙83+1∙82+3∙81+0∙80 = 1∙512+1∙64+3∙8+0∙1 = 512+64+24+0 = 60010
got It: 11308 =60010
Translate the number 60010 в binary like this:
the Integer part of the number is divided by the base of the new number system:
600 | 2 | | | | | | | | | |
-600 | 300 | 2 | | | | | | | | |
0 | -300 | 150 | 2 | | | | | | | |
| 0 | -150 | 75 | 2 | | | | | | |
| | 0 | -74 | 37 | 2 | | | | | |
| | | 1 | -36 | 18 | 2 | | | | |
| | | | 1 | -18 | 9 | 2 | | | |
| | | | | 0 | -8 | 4 | 2 | | |
| | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | 0 | -2 | 1 | |
| | | | | | | | 0 | | |
|
the result of the conversion was:
60010 = 10010110002
answer: 11308 = 10010110002