This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
7∙82+7∙81+6∙80 = 7∙64+7∙8+6∙1 = 448+56+6 = 51010
got It: 7768 =51010
Translate the number 51010 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
510 | 16 | | |
-496 | 31 | 16 | |
E | -16 | 1 | |
| F | | |
|
the result of the conversion was:
51010 = 1FE16
the Final answer: 7768 = 1FE16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
7768 = 7 7 6 = 7(=111) 7(=111) 6(=110) = 1111111102
the Final answer: 7768 = 1111111102
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0001111111102 = 0001 1111 1110 = 0001(=1) 1111(=F) 1110(=E) = 1FE16
the Final answer: 0001111111108 = 1FE16