This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
0b01116 = 0 b 0 1 1 = 0(=0000) b(=1011) 0(=0000) 1(=0001) 1(=0001) = 10110000000100012
the Final answer: 0b01116 = 10110000000100012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙164+11∙163+0∙162+1∙161+1∙160 = 0∙65536+11∙4096+0∙256+1∙16+1∙1 = 0+45056+0+16+1 = 4507310
got It: 0b01116 =4507310
Translate the number 4507310 в binary like this:
the Integer part of the number is divided by the base of the new number system:
45073 | 2 | | | | | | | | | | | | | | | |
-45072 | 22536 | 2 | | | | | | | | | | | | | | |
1 | -22536 | 11268 | 2 | | | | | | | | | | | | | |
| 0 | -11268 | 5634 | 2 | | | | | | | | | | | | |
| | 0 | -5634 | 2817 | 2 | | | | | | | | | | | |
| | | 0 | -2816 | 1408 | 2 | | | | | | | | | | |
| | | | 1 | -1408 | 704 | 2 | | | | | | | | | |
| | | | | 0 | -704 | 352 | 2 | | | | | | | | |
| | | | | | 0 | -352 | 176 | 2 | | | | | | | |
| | | | | | | 0 | -176 | 88 | 2 | | | | | | |
| | | | | | | | 0 | -88 | 44 | 2 | | | | | |
| | | | | | | | | 0 | -44 | 22 | 2 | | | | |
| | | | | | | | | | 0 | -22 | 11 | 2 | | | |
| | | | | | | | | | | 0 | -10 | 5 | 2 | | |
| | | | | | | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
4507310 = 10110000000100012
the Final answer: 0b01116 = 10110000000100012