This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙162+1∙161+6∙160 = 0∙256+1∙16+6∙1 = 0+16+6 = 2210
got It: 01616 =2210
Translate the number 2210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
22 | 8 | |
-16 | 2 | |
6 | | |
|
the result of the conversion was:
2210 = 268
the Final answer: 01616 = 268
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
01616 = 0 1 6 = 0(=0000) 1(=0001) 6(=0110) = 101102
the Final answer: 01616 = 101102
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0101102 = 010 110 = 010(=2) 110(=6) = 268
the Final answer: 01616 = 268