This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
3467108 = 3 4 6 7 1 0 = 3(=011) 4(=100) 6(=110) 7(=111) 1(=001) 0(=000) = 0111001101110010002
answer: 3467108 = 111001101110010002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
3∙85+4∙84+6∙83+7∙82+1∙81+0∙80 = 3∙32768+4∙4096+6∙512+7∙64+1∙8+0∙1 = 98304+16384+3072+448+8+0 = 11821610
got It: 3467108 =11821610
Translate the number 11821610 в binary like this:
the Integer part of the number is divided by the base of the new number system:
118216 | 2 | | | | | | | | | | | | | | | | |
-118216 | 59108 | 2 | | | | | | | | | | | | | | | |
0 | -59108 | 29554 | 2 | | | | | | | | | | | | | | |
| 0 | -29554 | 14777 | 2 | | | | | | | | | | | | | |
| | 0 | -14776 | 7388 | 2 | | | | | | | | | | | | |
| | | 1 | -7388 | 3694 | 2 | | | | | | | | | | | |
| | | | 0 | -3694 | 1847 | 2 | | | | | | | | | | |
| | | | | 0 | -1846 | 923 | 2 | | | | | | | | | |
| | | | | | 1 | -922 | 461 | 2 | | | | | | | | |
| | | | | | | 1 | -460 | 230 | 2 | | | | | | | |
| | | | | | | | 1 | -230 | 115 | 2 | | | | | | |
| | | | | | | | | 0 | -114 | 57 | 2 | | | | | |
| | | | | | | | | | 1 | -56 | 28 | 2 | | | | |
| | | | | | | | | | | 1 | -28 | 14 | 2 | | | |
| | | | | | | | | | | | 0 | -14 | 7 | 2 | | |
| | | | | | | | | | | | | 0 | -6 | 3 | 2 | |
| | | | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | | | 1 | | |
|
the result of the conversion was:
11821610 = 111001101110010002
answer: 3467108 = 111001101110010002