This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
0∙811+0∙810+0∙89+1∙88+1∙87+0∙86+1∙85+1∙84+0∙83+1∙82+1∙81+0∙80 = 0∙8589934592+0∙1073741824+0∙134217728+1∙16777216+1∙2097152+0∙262144+1∙32768+1∙4096+0∙512+1∙64+1∙8+0∙1 = 0+0+0+16777216+2097152+0+32768+4096+0+64+8+0 = 1891130410
got It: 0001101101108 =1891130410
Translate the number 1891130410 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
18911304 | 16 | | | | | | |
-18911296 | 1181956 | 16 | | | | | |
8 | -1181952 | 73872 | 16 | | | | |
| 4 | -73872 | 4617 | 16 | | | |
| | 0 | -4608 | 288 | 16 | | |
| | | 9 | -288 | 18 | 16 | |
| | | | 0 | -16 | 1 | |
| | | | | 2 | | |
|
the result of the conversion was:
1891130410 = 120904816
the Final answer: 0001101101108 = 120904816
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
0001101101108 = 0 0 0 1 1 0 1 1 0 1 1 0 = 0(=000) 0(=000) 0(=000) 1(=001) 1(=001) 0(=000) 1(=001) 1(=001) 0(=000) 1(=001) 1(=001) 0(=000) = 0000000000010010000010010000010010002
the Final answer: 0001101101108 = 10010000010010000010010002
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
00010010000010010000010010002 = 0001 0010 0000 1001 0000 0100 1000 = 0001(=1) 0010(=2) 0000(=0) 1001(=9) 0000(=0) 0100(=4) 1000(=8) = 120904816
the Final answer: 00010010000010010000010010008 = 120904816