This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙163+1∙162+2∙161+5∙160 = 0∙4096+1∙256+2∙16+5∙1 = 0+256+32+5 = 29310
got It: 012516 =29310
Translate the number 29310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
293 | 8 | | |
-288 | 36 | 8 | |
5 | -32 | 4 | |
| 4 | | |
|
the result of the conversion was:
29310 = 4458
answer: 012516 = 4458
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
012516 = 0 1 2 5 = 0(=0000) 1(=0001) 2(=0010) 5(=0101) = 1001001012
answer: 012516 = 1001001012
let\'s make a direct translation from binary to post-binary like this:
1001001012 = 100 100 101 = 100(=4) 100(=4) 101(=5) = 4458
answer: 012516 = 4458