This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙82+3∙81+2∙80 = 2∙64+3∙8+2∙1 = 128+24+2 = 15410
got It: 2328 =15410
Translate the number 15410 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
154 | 16 | |
-144 | 9 | |
A | | |
|
the result of the conversion was:
15410 = 9A16
the Final answer: 2328 = 9A16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
2328 = 2 3 2 = 2(=010) 3(=011) 2(=010) = 0100110102
the Final answer: 2328 = 100110102
let\'s do a direct translation from binary to hexadecimal like this:
100110102 = 1001 1010 = 1001(=9) 1010(=A) = 9A16
the Final answer: 100110108 = 9A16