This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
11.1018 = 1 1. 1 0 1 = 1(=001) 1(=001). 1(=001) 0(=000) 1(=001) = 001001.0010000012
the Final answer: 11.1018 = 1001.0010000012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙81+1∙80+1∙8-1+0∙8-2+1∙8-3 = 1∙8+1∙1+1∙0.125+0∙0.015625+1∙0.001953125 = 8+1+0.125+0+0.001953125 = 9.12695312510
got It: 11.1018 =9.12695312510
Translate the number 9.12695312510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
9 | 2 | | | |
-8 | 4 | 2 | | |
1 | -4 | 2 | 2 | |
| 0 | -2 | 1 | |
| | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 126953125*2 |
0 | .25391*2 |
0 | .50781*2 |
1 | .01563*2 |
0 | .03125*2 |
0 | .0625*2 |
0 | .125*2 |
0 | .25*2 |
0 | .5*2 |
1 | .0*2 |
the result of the conversion was:
9.12695312510 = 1001.0010000012
the Final answer: 11.1018 = 1001.0010000012