This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
9∙162+15∙161+10∙160 = 9∙256+15∙16+10∙1 = 2304+240+10 = 255410
got It: 9FA16 =255410
Translate the number 255410 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2554 | 8 | | | |
-2552 | 319 | 8 | | |
2 | -312 | 39 | 8 | |
| 7 | -32 | 4 | |
| | 7 | | |
|
the result of the conversion was:
255410 = 47728
answer: 9FA16 = 47728
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
9FA16 = 9 F A = 9(=1001) F(=1111) A(=1010) = 1001111110102
answer: 9FA16 = 1001111110102
let\'s make a direct translation from binary to post-binary like this:
1001111110102 = 100 111 111 010 = 100(=4) 111(=7) 111(=7) 010(=2) = 47728
answer: 9FA16 = 47728