This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
2∙83+0∙82+1∙81+7∙80 = 2∙512+0∙64+1∙8+7∙1 = 1024+0+8+7 = 103910
got It: 20178 =103910
Translate the number 103910 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
1039 | 16 | | |
-1024 | 64 | 16 | |
F | -64 | 4 | |
| 0 | | |
|
the result of the conversion was:
103910 = 40F16
answer: 20178 = 40F16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
20178 = 2 0 1 7 = 2(=010) 0(=000) 1(=001) 7(=111) = 0100000011112
answer: 20178 = 100000011112
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0100000011112 = 0100 0000 1111 = 0100(=4) 0000(=0) 1111(=F) = 40F16
answer: 0100000011118 = 40F16