This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
1∙82+5∙81+6∙80 = 1∙64+5∙8+6∙1 = 64+40+6 = 11010
got It: 1568 =11010
Translate the number 11010 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
110 | 16 | |
-96 | 6 | |
E | | |
|
the result of the conversion was:
11010 = 6E16
answer: 1568 = 6E16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
1568 = 1 5 6 = 1(=001) 5(=101) 6(=110) = 0011011102
answer: 1568 = 11011102
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
011011102 = 0110 1110 = 0110(=6) 1110(=E) = 6E16
answer: 011011108 = 6E16