This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙163+0∙162+15∙161+0∙160 = 0∙4096+0∙256+15∙16+0∙1 = 0+0+240+0 = 24010
got It: 00F016 =24010
Translate the number 24010 в octal like this:
the Integer part of the number is divided by the base of the new number system:
240 | 8 | | |
-240 | 30 | 8 | |
0 | -24 | 3 | |
| 6 | | |
|
the result of the conversion was:
24010 = 3608
answer: 00F016 = 3608
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
00F016 = 0 0 F 0 = 0(=0000) 0(=0000) F(=1111) 0(=0000) = 111100002
answer: 00F016 = 111100002
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0111100002 = 011 110 000 = 011(=3) 110(=6) 000(=0) = 3608
answer: 00F016 = 3608