This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
14∙162+13∙161+5∙160+12∙16-1+10∙16-2 = 14∙256+13∙16+5∙1+12∙0.0625+10∙0.00390625 = 3584+208+5+0.75+0.0390625 = 3797.789062510
got It: ED5.CA16 =3797.789062510
Translate the number 3797.789062510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
3797 | 8 | | | |
-3792 | 474 | 8 | | |
5 | -472 | 59 | 8 | |
| 2 | -56 | 7 | |
| | 3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 7890625*8 |
6 | .3125*8 |
2 | .5*8 |
4 | .0*8 |
the result of the conversion was:
3797.789062510 = 7325.6248
answer: ED5.CA16 = 7325.6248
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
ED5.CA16 = E D 5. C A = E(=1110) D(=1101) 5(=0101). C(=1100) A(=1010) = 111011010101.11001012
answer: ED5.CA16 = 111011010101.11001012
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
111011010101.1100101002 = 111 011 010 101. 110 010 100 = 111(=7) 011(=3) 010(=2) 101(=5). 110(=6) 010(=2) 100(=4) = 7325.6248
answer: ED5.CA16 = 7325.6248