This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
01111001111100012 = 0111 1001 1111 0001 = 0111(=7) 1001(=9) 1111(=F) 0001(=1) = 79F116
answer: 01111001111100012 = 79F116
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙215+1∙214+1∙213+1∙212+1∙211+0∙210+0∙29+1∙28+1∙27+1∙26+1∙25+1∙24+0∙23+0∙22+0∙21+1∙20 = 0∙32768+1∙16384+1∙8192+1∙4096+1∙2048+0∙1024+0∙512+1∙256+1∙128+1∙64+1∙32+1∙16+0∙8+0∙4+0∙2+1∙1 = 0+16384+8192+4096+2048+0+0+256+128+64+32+16+0+0+0+1 = 3121710
got It: 01111001111100012 =3121710
Translate the number 3121710 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
31217 | 16 | | | |
-31216 | 1951 | 16 | | |
1 | -1936 | 121 | 16 | |
| F | -112 | 7 | |
| | 9 | | |
|
the result of the conversion was:
3121710 = 79F116
answer: 01111001111100012 = 79F116