This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
14∙161+2∙160 = 14∙16+2∙1 = 224+2 = 22610
got It: E216 =22610
Translate the number 22610 в octal like this:
the Integer part of the number is divided by the base of the new number system:
226 | 8 | | |
-224 | 28 | 8 | |
2 | -24 | 3 | |
| 4 | | |
|
the result of the conversion was:
22610 = 3428
answer: E216 = 3428
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
E216 = E 2 = E(=1110) 2(=0010) = 111000102
answer: E216 = 111000102
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0111000102 = 011 100 010 = 011(=3) 100(=4) 010(=2) = 3428
answer: E216 = 3428