This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011111010110111102 = 001 111 101 011 011 110 = 001(=1) 111(=7) 101(=5) 011(=3) 011(=3) 110(=6) = 1753368
answer: 11111010110111102 = 1753368
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙217+0∙216+1∙215+1∙214+1∙213+1∙212+1∙211+0∙210+1∙29+0∙28+1∙27+1∙26+0∙25+1∙24+1∙23+1∙22+1∙21+0∙20 = 0∙131072+0∙65536+1∙32768+1∙16384+1∙8192+1∙4096+1∙2048+0∙1024+1∙512+0∙256+1∙128+1∙64+0∙32+1∙16+1∙8+1∙4+1∙2+0∙1 = 0+0+32768+16384+8192+4096+2048+0+512+0+128+64+0+16+8+4+2+0 = 6422210
got It: 0011111010110111102 =6422210
Translate the number 6422210 в octal like this:
the Integer part of the number is divided by the base of the new number system:
64222 | 8 | | | | | |
-64216 | 8027 | 8 | | | | |
6 | -8024 | 1003 | 8 | | | |
| 3 | -1000 | 125 | 8 | | |
| | 3 | -120 | 15 | 8 | |
| | | 5 | -8 | 1 | |
| | | | 7 | | |
|
the result of the conversion was:
6422210 = 1753368
answer: 11111010110111102 = 1753368