This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
14∙161+13∙160+10∙16-1+12∙16-2 = 14∙16+13∙1+10∙0.0625+12∙0.00390625 = 224+13+0.625+0.046875 = 237.67187510
got It: ED.AC16 =237.67187510
Translate the number 237.67187510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
237 | 8 | | |
-232 | 29 | 8 | |
5 | -24 | 3 | |
| 5 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 671875*8 |
5 | .375*8 |
3 | .0*8 |
the result of the conversion was:
237.67187510 = 355.538
answer: ED.AC16 = 355.538
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
ED.AC16 = E D. A C = E(=1110) D(=1101). A(=1010) C(=1100) = 11101101.1010112
answer: ED.AC16 = 11101101.1010112
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
011101101.1010112 = 011 101 101. 101 011 = 011(=3) 101(=5) 101(=5). 101(=5) 011(=3) = 355.538
answer: ED.AC16 = 355.538