This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
001011016 = 0 0 1 0 1 1 0 = 0(=0000) 0(=0000) 1(=0001) 0(=0000) 1(=0001) 1(=0001) 0(=0000) = 100000001000100002
the Final answer: 001011016 = 100000001000100002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙166+0∙165+1∙164+0∙163+1∙162+1∙161+0∙160 = 0∙16777216+0∙1048576+1∙65536+0∙4096+1∙256+1∙16+0∙1 = 0+0+65536+0+256+16+0 = 6580810
got It: 001011016 =6580810
Translate the number 6580810 в binary like this:
the Integer part of the number is divided by the base of the new number system:
65808 | 2 | | | | | | | | | | | | | | | | |
-65808 | 32904 | 2 | | | | | | | | | | | | | | | |
0 | -32904 | 16452 | 2 | | | | | | | | | | | | | | |
| 0 | -16452 | 8226 | 2 | | | | | | | | | | | | | |
| | 0 | -8226 | 4113 | 2 | | | | | | | | | | | | |
| | | 0 | -4112 | 2056 | 2 | | | | | | | | | | | |
| | | | 1 | -2056 | 1028 | 2 | | | | | | | | | | |
| | | | | 0 | -1028 | 514 | 2 | | | | | | | | | |
| | | | | | 0 | -514 | 257 | 2 | | | | | | | | |
| | | | | | | 0 | -256 | 128 | 2 | | | | | | | |
| | | | | | | | 1 | -128 | 64 | 2 | | | | | | |
| | | | | | | | | 0 | -64 | 32 | 2 | | | | | |
| | | | | | | | | | 0 | -32 | 16 | 2 | | | | |
| | | | | | | | | | | 0 | -16 | 8 | 2 | | | |
| | | | | | | | | | | | 0 | -8 | 4 | 2 | | |
| | | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
6580810 = 100000001000100002
the Final answer: 001011016 = 100000001000100002