This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
Dc416 = D c 4 = D(=1101) c(=1100) 4(=0100) = 1101110001002
answer: Dc416 = 1101110001002
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
13∙162+12∙161+4∙160 = 13∙256+12∙16+4∙1 = 3328+192+4 = 352410
got It: Dc416 =352410
Translate the number 352410 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3524 | 2 | | | | | | | | | | | |
-3524 | 1762 | 2 | | | | | | | | | | |
0 | -1762 | 881 | 2 | | | | | | | | | |
| 0 | -880 | 440 | 2 | | | | | | | | |
| | 1 | -440 | 220 | 2 | | | | | | | |
| | | 0 | -220 | 110 | 2 | | | | | | |
| | | | 0 | -110 | 55 | 2 | | | | | |
| | | | | 0 | -54 | 27 | 2 | | | | |
| | | | | | 1 | -26 | 13 | 2 | | | |
| | | | | | | 1 | -12 | 6 | 2 | | |
| | | | | | | | 1 | -6 | 3 | 2 | |
| | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | 1 | | |
|
the result of the conversion was:
352410 = 1101110001002
answer: Dc416 = 1101110001002