This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
0∙160+6∙16-1+8∙16-2 = 0∙1+6∙0.0625+8∙0.00390625 = 0+0.375+0.03125 = 0.4062510
got It: 0.6816 =0.4062510
Translate the number 0.4062510 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 40625*8 |
3 | .25*8 |
2 | .0*8 |
the result of the conversion was:
0.4062510 = 0.328
answer: 0.6816 = 0.328
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
0.6816 = 0. 6 8 = 0(=0000). 6(=0110) 8(=1000) = .011012
answer: 0.6816 = .011012
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
.0110102 = . 011 010 = . 011(=3) 010(=2) = .328
answer: 0.6816 = .328