This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
57318 = 5 7 3 1 = 5(=101) 7(=111) 3(=011) 1(=001) = 1011110110012
answer: 57318 = 1011110110012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
5∙83+7∙82+3∙81+1∙80 = 5∙512+7∙64+3∙8+1∙1 = 2560+448+24+1 = 303310
got It: 57318 =303310
Translate the number 303310 в binary like this:
the Integer part of the number is divided by the base of the new number system:
3033 | 2 | | | | | | | | | | | |
-3032 | 1516 | 2 | | | | | | | | | | |
1 | -1516 | 758 | 2 | | | | | | | | | |
| 0 | -758 | 379 | 2 | | | | | | | | |
| | 0 | -378 | 189 | 2 | | | | | | | |
| | | 1 | -188 | 94 | 2 | | | | | | |
| | | | 1 | -94 | 47 | 2 | | | | | |
| | | | | 0 | -46 | 23 | 2 | | | | |
| | | | | | 1 | -22 | 11 | 2 | | | |
| | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | 0 | | |
|
the result of the conversion was:
303310 = 1011110110012
answer: 57318 = 1011110110012