This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
4∙82+5∙81+6∙80+7∙8-1+3∙8-2 = 4∙64+5∙8+6∙1+7∙0.125+3∙0.015625 = 256+40+6+0.875+0.046875 = 302.92187510
got It: 456.738 =302.92187510
Translate the number 302.92187510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
302 | 16 | | |
-288 | 18 | 16 | |
E | -16 | 1 | |
| 2 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 921875*16 |
E | .75*16 |
C | .0*16 |
the result of the conversion was:
302.92187510 = 12E.EC16
answer: 456.738 = 12E.EC16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
456.738 = 4 5 6. 7 3 = 4(=100) 5(=101) 6(=110). 7(=111) 3(=011) = 100101110.1110112
answer: 456.738 = 100101110.1110112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
000100101110.111011002 = 0001 0010 1110. 1110 1100 = 0001(=1) 0010(=2) 1110(=E). 1110(=E) 1100(=C) = 12E.EC16
answer: 000100101110.111011008 = 12E.EC16