This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
8FE316 = 8 F E 3 = 8(=1000) F(=1111) E(=1110) 3(=0011) = 10001111111000112
answer: 8FE316 = 10001111111000112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
8∙163+15∙162+14∙161+3∙160 = 8∙4096+15∙256+14∙16+3∙1 = 32768+3840+224+3 = 3683510
got It: 8FE316 =3683510
Translate the number 3683510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
36835 | 2 | | | | | | | | | | | | | | | |
-36834 | 18417 | 2 | | | | | | | | | | | | | | |
1 | -18416 | 9208 | 2 | | | | | | | | | | | | | |
| 1 | -9208 | 4604 | 2 | | | | | | | | | | | | |
| | 0 | -4604 | 2302 | 2 | | | | | | | | | | | |
| | | 0 | -2302 | 1151 | 2 | | | | | | | | | | |
| | | | 0 | -1150 | 575 | 2 | | | | | | | | | |
| | | | | 1 | -574 | 287 | 2 | | | | | | | | |
| | | | | | 1 | -286 | 143 | 2 | | | | | | | |
| | | | | | | 1 | -142 | 71 | 2 | | | | | | |
| | | | | | | | 1 | -70 | 35 | 2 | | | | | |
| | | | | | | | | 1 | -34 | 17 | 2 | | | | |
| | | | | | | | | | 1 | -16 | 8 | 2 | | | |
| | | | | | | | | | | 1 | -8 | 4 | 2 | | |
| | | | | | | | | | | | 0 | -4 | 2 | 2 | |
| | | | | | | | | | | | | 0 | -2 | 1 | |
| | | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
3683510 = 10001111111000112
answer: 8FE316 = 10001111111000112