This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0111111100012 = 011 111 110 001 = 011(=3) 111(=7) 110(=6) 001(=1) = 37618
answer: 111111100012 = 37618
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+1∙210+1∙29+1∙28+1∙27+1∙26+1∙25+1∙24+0∙23+0∙22+0∙21+1∙20 = 0∙2048+1∙1024+1∙512+1∙256+1∙128+1∙64+1∙32+1∙16+0∙8+0∙4+0∙2+1∙1 = 0+1024+512+256+128+64+32+16+0+0+0+1 = 203310
got It: 0111111100012 =203310
Translate the number 203310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2033 | 8 | | | |
-2032 | 254 | 8 | | |
1 | -248 | 31 | 8 | |
| 6 | -24 | 3 | |
| | 7 | | |
|
the result of the conversion was:
203310 = 37618
answer: 111111100012 = 37618