This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1101011101102 = 110 101 110 110 = 110(=6) 101(=5) 110(=6) 110(=6) = 65668
answer: 1101011101102 = 65668
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙211+1∙210+0∙29+1∙28+0∙27+1∙26+1∙25+1∙24+0∙23+1∙22+1∙21+0∙20 = 1∙2048+1∙1024+0∙512+1∙256+0∙128+1∙64+1∙32+1∙16+0∙8+1∙4+1∙2+0∙1 = 2048+1024+0+256+0+64+32+16+0+4+2+0 = 344610
got It: 1101011101102 =344610
Translate the number 344610 в octal like this:
the Integer part of the number is divided by the base of the new number system:
3446 | 8 | | | |
-3440 | 430 | 8 | | |
6 | -424 | 53 | 8 | |
| 6 | -48 | 6 | |
| | 5 | | |
|
the result of the conversion was:
344610 = 65668
answer: 1101011101102 = 65668