This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
4538 = 4 5 3 = 4(=100) 5(=101) 3(=011) = 1001010112
answer: 4538 = 1001010112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
4∙82+5∙81+3∙80 = 4∙64+5∙8+3∙1 = 256+40+3 = 29910
got It: 4538 =29910
Translate the number 29910 в binary like this:
the Integer part of the number is divided by the base of the new number system:
299 | 2 | | | | | | | | |
-298 | 149 | 2 | | | | | | | |
1 | -148 | 74 | 2 | | | | | | |
| 1 | -74 | 37 | 2 | | | | | |
| | 0 | -36 | 18 | 2 | | | | |
| | | 1 | -18 | 9 | 2 | | | |
| | | | 0 | -8 | 4 | 2 | | |
| | | | | 1 | -4 | 2 | 2 | |
| | | | | | 0 | -2 | 1 | |
| | | | | | | 0 | | |
|
the result of the conversion was:
29910 = 1001010112
answer: 4538 = 1001010112