This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
12∙162+10∙161+15∙160 = 12∙256+10∙16+15∙1 = 3072+160+15 = 324710
got It: caf16 =324710
Translate the number 324710 в octal like this:
the Integer part of the number is divided by the base of the new number system:
3247 | 8 | | | |
-3240 | 405 | 8 | | |
7 | -400 | 50 | 8 | |
| 5 | -48 | 6 | |
| | 2 | | |
|
the result of the conversion was:
324710 = 62578
answer: caf16 = 62578
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
caf16 = c a f = c(=1100) a(=1010) f(=1111) = 1100101011112
answer: caf16 = 1100101011112
let\'s make a direct translation from binary to post-binary like this:
1100101011112 = 110 010 101 111 = 110(=6) 010(=2) 101(=5) 111(=7) = 62578
answer: caf16 = 62578