This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011011010112 = 001 101 101 011 = 001(=1) 101(=5) 101(=5) 011(=3) = 15538
answer: 11011010112 = 15538
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙211+0∙210+1∙29+1∙28+0∙27+1∙26+1∙25+0∙24+1∙23+0∙22+1∙21+1∙20 = 0∙2048+0∙1024+1∙512+1∙256+0∙128+1∙64+1∙32+0∙16+1∙8+0∙4+1∙2+1∙1 = 0+0+512+256+0+64+32+0+8+0+2+1 = 87510
got It: 0011011010112 =87510
Translate the number 87510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
875 | 8 | | | |
-872 | 109 | 8 | | |
3 | -104 | 13 | 8 | |
| 5 | -8 | 1 | |
| | 5 | | |
|
the result of the conversion was:
87510 = 15538
answer: 11011010112 = 15538