This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
5FA716 = 5 F A 7 = 5(=0101) F(=1111) A(=1010) 7(=0111) = 1011111101001112
answer: 5FA716 = 1011111101001112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
5∙163+15∙162+10∙161+7∙160 = 5∙4096+15∙256+10∙16+7∙1 = 20480+3840+160+7 = 2448710
got It: 5FA716 =2448710
Translate the number 2448710 в binary like this:
the Integer part of the number is divided by the base of the new number system:
24487 | 2 | | | | | | | | | | | | | | |
-24486 | 12243 | 2 | | | | | | | | | | | | | |
1 | -12242 | 6121 | 2 | | | | | | | | | | | | |
| 1 | -6120 | 3060 | 2 | | | | | | | | | | | |
| | 1 | -3060 | 1530 | 2 | | | | | | | | | | |
| | | 0 | -1530 | 765 | 2 | | | | | | | | | |
| | | | 0 | -764 | 382 | 2 | | | | | | | | |
| | | | | 1 | -382 | 191 | 2 | | | | | | | |
| | | | | | 0 | -190 | 95 | 2 | | | | | | |
| | | | | | | 1 | -94 | 47 | 2 | | | | | |
| | | | | | | | 1 | -46 | 23 | 2 | | | | |
| | | | | | | | | 1 | -22 | 11 | 2 | | | |
| | | | | | | | | | 1 | -10 | 5 | 2 | | |
| | | | | | | | | | | 1 | -4 | 2 | 2 | |
| | | | | | | | | | | | 1 | -2 | 1 | |
| | | | | | | | | | | | | 0 | | |
|
the result of the conversion was:
2448710 = 1011111101001112
answer: 5FA716 = 1011111101001112