This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0100111101000011012 = 010 011 110 100 001 101 = 010(=2) 011(=3) 110(=6) 100(=4) 001(=1) 101(=5) = 2364158
answer: 100111101000011012 = 2364158
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙217+1∙216+0∙215+0∙214+1∙213+1∙212+1∙211+1∙210+0∙29+1∙28+0∙27+0∙26+0∙25+0∙24+1∙23+1∙22+0∙21+1∙20 = 0∙131072+1∙65536+0∙32768+0∙16384+1∙8192+1∙4096+1∙2048+1∙1024+0∙512+1∙256+0∙128+0∙64+0∙32+0∙16+1∙8+1∙4+0∙2+1∙1 = 0+65536+0+0+8192+4096+2048+1024+0+256+0+0+0+0+8+4+0+1 = 8116510
got It: 0100111101000011012 =8116510
Translate the number 8116510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
81165 | 8 | | | | | |
-81160 | 10145 | 8 | | | | |
5 | -10144 | 1268 | 8 | | | |
| 1 | -1264 | 158 | 8 | | |
| | 4 | -152 | 19 | 8 | |
| | | 6 | -16 | 2 | |
| | | | 3 | | |
|
the result of the conversion was:
8116510 = 2364158
answer: 100111101000011012 = 2364158