This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
3∙163+8∙162+1∙161+11∙160 = 3∙4096+8∙256+1∙16+11∙1 = 12288+2048+16+11 = 1436310
got It: 381b16 =1436310
Translate the number 1436310 в octal like this:
the Integer part of the number is divided by the base of the new number system:
14363 | 8 | | | | |
-14360 | 1795 | 8 | | | |
3 | -1792 | 224 | 8 | | |
| 3 | -224 | 28 | 8 | |
| | 0 | -24 | 3 | |
| | | 4 | | |
|
the result of the conversion was:
1436310 = 340338
answer: 381b16 = 340338
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
381b16 = 3 8 1 b = 3(=0011) 8(=1000) 1(=0001) b(=1011) = 111000000110112
answer: 381b16 = 111000000110112
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0111000000110112 = 011 100 000 011 011 = 011(=3) 100(=4) 000(=0) 011(=3) 011(=3) = 340338
answer: 381b16 = 340338