This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0010101010001111100102 = 001 010 101 000 111 110 010 = 001(=1) 010(=2) 101(=5) 000(=0) 111(=7) 110(=6) 010(=2) = 12507628
answer: 10101010001111100102 = 12507628
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙220+0∙219+1∙218+0∙217+1∙216+0∙215+1∙214+0∙213+1∙212+0∙211+0∙210+0∙29+1∙28+1∙27+1∙26+1∙25+1∙24+0∙23+0∙22+1∙21+0∙20 = 0∙1048576+0∙524288+1∙262144+0∙131072+1∙65536+0∙32768+1∙16384+0∙8192+1∙4096+0∙2048+0∙1024+0∙512+1∙256+1∙128+1∙64+1∙32+1∙16+0∙8+0∙4+1∙2+0∙1 = 0+0+262144+0+65536+0+16384+0+4096+0+0+0+256+128+64+32+16+0+0+2+0 = 34865810
got It: 0010101010001111100102 =34865810
Translate the number 34865810 в octal like this:
the Integer part of the number is divided by the base of the new number system:
348658 | 8 | | | | | | |
-348656 | 43582 | 8 | | | | | |
2 | -43576 | 5447 | 8 | | | | |
| 6 | -5440 | 680 | 8 | | | |
| | 7 | -680 | 85 | 8 | | |
| | | 0 | -80 | 10 | 8 | |
| | | | 5 | -8 | 1 | |
| | | | | 2 | | |
|
the result of the conversion was:
34865810 = 12507628
answer: 10101010001111100102 = 12507628